A metal surface is illuminated by a light of given intensity and frequency to cause photoemission. If the intensity of illumination is reduced to one-fourth of its original value,then the maximum KE of emitted photoelectrons will become
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a
(l/16)th of original value
b
unchanged
c
twice the original value
d
four times the original value
answer is B.
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Detailed Solution
Maximum KE depends on the frequency of incident radiation, not on intensity.