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Q.

A metal wire of length L1 and area of cross-section A is attached to a rigid support. Another metal wire of length L2 and of the same cross-sectional area is attached to the free end of the first wire. A body of mass M is then suspended from the free end of the second wire. If Y1 and Y2 are the Young's moduli of the wires respectively, the effective force constant of the system of two wires is

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a

Y1Y2A2Y1L2+Y2L1

b

Y1Y2AL1L21/2

c

Y1Y2AY1L2+Y2L1

d

Y1Y21/2AL1L21/2

answer is C.

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Detailed Solution

Using the usual expression for the Young's modulus, the force constant for the wire can be written ask=FΔL=YALwhere the symbols have their usual meanings.When the two wires are connected together in series, the effective force constant is given by keq =k1k2k1+k2Substituting the corresponding lengths, area of cross sections and the Young's moduli, we get keq=Y1AL1Y2AL2Y1AL1+Y2AL2=Y1Y2AY1L2+Y2L1
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