A metal wire of linear mass density of $$9.8$$ $$g/m$$ is stretched with a tension of $$10$$ kg weight between two rigid supports $$1$$ metre apart. The wire passes at its middle point between the poles of a permanent magnet, and it vibrates in resonance when carrying an alternating current of frequency n. The frequency n of the alternating source is

Question

Infinity Learn · Accepted Answer

In condition of resonance, frequency of a.c. will be equal to natural frequency of wire  $$n=12lTm=12$$×$$110$$×$$9.89.8$$×$$10$$−$$3=1002=50$$ Hz

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