A metal wire of linear mass density of 9.8 g/m is stretched with a tension of 10 kg weight between two rigid supports 1 metre apart. The wire passes at its middle point between the poles of a permanent magnet, and it vibrates in resonance when carrying an alternating current of frequency n. The frequency n of the alternating source is

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25 Hz

50 Hz

100 Hz

200 Hz

answer is B.

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Detailed Solution

In condition of resonance, frequency of a.c. will be equal to natural frequency of wire n=12lTm=12×110×9.89.8×10−3=1002=50 Hz

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