A metal wire of mass m slides without friction on two rails spaced at a distance d apart. The track lies in a vertical uniform magnetic field B. A constant current I flows along one rail, across the wire and back down the other rail. If the wire is initially at rest, the time taken by it to move through a distance x along the track is
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a
t=BId2xm
b
t=2xmBId
c
t=BIdm2x
d
t=2dmBIx
answer is B.
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Detailed Solution
Force acting on the wire is F = IdB a = IdB/mx=12at2t=2xa=2xmIdB