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A metallic ring of radius 1 m is placed in a uniform magnetic field of induction 1μT  with its plane perpendicular to the direction of magnetic field. Now the radius of the ring is halved in a time interval of 0.1 second. Then average emf induced in the ring is

a
7.5 μV
b
12 πμV
c
25 πμV
d
15.5 πμV

detailed solution

Correct option is A

Average emf =B.πr2  −  B.πr/22Δt=34  πr2.  BΔt=34  π12 .  10.1  μV=   7.5   π μ.V

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