Questions
A metallic ring of radius r with a uniform metallic spoke of negligible mass and length r is rotated about its axis with angular velocity in a perpendicular uniform magnetic field B as shown in figure. The central end of the spoke is connected to the rim of the wheel through a resistor R as shown. The resistor does not rotate, its one end is always at the center of the ring and the other end is always in contact with the ring. A force F as shown is needed to maintain constant angular velocity of the wheel. F is equal to (the ring and the spoke has zero resistance)
detailed solution
Correct option is D
Induced emf in the spoke is shown in figure below.e=12Bωr2,I=eR=Bωr22RThere will be no induced emf separately in parts ADC or AEC.Fb=IrB=B2ωr32RBalancing torque about E: Fr=Fbr/2⇒ F=Fb2=B2ωr34RNote: Force due to current s I/2 will act on circular parts also, but their torque about E will be zero.Talk to our academic expert!
Similar Questions
The diagram shows a circuit having a coil of resistance and inductance L connected to a conducting rod PQ which can slide on a perfectly conducting circular ring of radius 10 cm with its centre at 'P'. Assume that friction and gravity are absent and a constant uniform magnetic field of 5 T exists as shown in figure.
At t = 0, the circuit is switched on and simultaneously a time varying external torque is applied on the rod so that it rotates about P with a constant angular velocity 40 rad/s. Find magnitude of this torque (in milli Nm) when current reaches half of its maximum value. Neglect the self-inductance of the loop formed by the circuit.
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