Questions
A metallic sphere cools from C to C in 300s. If atmospheric temperature around is C, then the sphere’s temperature after the next 5 minutes will be close to :
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Correct option is B
Newton's Law of Cooling, θ1−θ2t1−t2=kθ1+θ22−θsur⇒50−40300=k50+402−20⇒10300=k45−20−−−1Now, 40−θf300=k40+θf2−20−−−−−2Dividing1 by 2, 1040−θf=2540+θf2−20⇒1040−θf=25θf×2⇒θf=1003=330CSimilar Questions
A body cools down from 60°C to 55°C in 30 s. Using Newton’s law of cooling, calculate the approximate time taken by same body to cool down from 5 5°C
to 50°C. Assume that the temperature of surroundings is 45°C.
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