A metallic square loop ABCD is moving in its own plane with velocity v in a uniform magnetic field perpendicular to its plane as shown in fig. Anelectric field is induced
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a
in AD, but not in BC
b
in BC, but not in AD
c
neither in AD nor in BC
d
in both AD and BC
answer is D.
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Detailed Solution
Here VD−VA=VC−VB=Blv (motional e.m.f.)So, the electric field is induced in both AD and BC.
A metallic square loop ABCD is moving in its own plane with velocity v in a uniform magnetic field perpendicular to its plane as shown in fig. Anelectric field is induced