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Q.

A metallic surface is illuminated with monochromatic light of wavelength λ and stopping potential for photoelectric current is 5vo  when the same metallic surface is illuminated with a light of wavelength 2λ , the stopping potential is Vo . What is the threshold wavelength for the surface ?

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a

8λ3

b

8λ

c

5λ

d

3λ

answer is A.

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Detailed Solution

hcλ=ϕ+e5Vo ...1hc2λ=ϕ+eVo ...2∴2ϕ+eVo=ϕ+5eVo⇒ϕ=3eVo⇒hcλo=3eVo⇒λo=hc3eVoFrom (1)   hcλ=3eVo+5eVo⇒hc3eVo=8λ3∴ λo=8λ3
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