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A metallic wire has a resistance of 10 Ω . when the wire is stretched to twice its original length, resistivity of its material increases by 10%. Then the new resistance is

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answer is 4.

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Detailed Solution

R=ρ.lA and l'A'=lA⇒A'=lAl'R'=ρ'.l'A' =1.10ρlA.l'l2=1.10Rl'l2⇒R'=1.1 x 10 x (2)2 Ω=44Ω

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