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In a meter bridge circuit as shown, when one more resistance of 100 Ω is connected is parallel with unknown resistance x, then ratio l1l2become 2. If l1 is balance length of the uniform wire A B, then the value of x must be:
 



 

a
50 Ω
b
100 Ω
c
200 Ω
d
400 Ω

detailed solution

Correct option is B

∵wheat stone bridge is in balanced conditionSo 100ℓ1=100x100+xℓ2∵ℓ1ℓ2=2 ⇒x=100Ω

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