In a meter bridge experiment S is a standard resistance. R is a resistance wire. It is found that balancing length is l=25cm. If R is replaced by a wire of half length and half diameter that of R of same material, then the balancing distance l'(in cm) will now be_______

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answer is 0040.00.

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Detailed Solution

RS=L100−L=2575 ⇒R=13S Also, R=ρLA=ρLπr2New value=R1=ρ.L2πr22=2R Now , 2RS=L1100−L1 ⇒2.S/3S=L1100−L1⇒23=L1100−L1 ⇒200−2L11=3L11 ⇒L1=40cm

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