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In a meter bridge experiment S is a standard resistance. R is a resistance wire. It is found that balancing length is l = 25 cm . If ‘R’ is replaced by a wire of half length and same diameter that of R of same material. Then the balancing distance l in cm will now be

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answer is 0014.29.

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Detailed Solution

Initially, SR=7525=3 Now, R=ρlA=4ρlπd2 ∴ R'=4ρl/2πd2=R2 Finally, SR'=100−ll ⇒SR/2=100−ll ⇒2SR=100−ll ⇒2×3=100−ll ⇒l=1007=14.29 cm

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