In a meter bridge, the gaps are closed by two resistances P and Q and the balance point is obtained at $40 c m$ . when Q is shunted by a resistance of $10 Ω$ , the balance point shifts to $50 c m$ . the values of P and Q are

Question

Infinity Learn · Accepted Answer

For  meter bridge to be balanced  $$PQ=l100$$−l     $$PQ=4060=23$$     ⇒$$P=23Q$$     When  Q is shunted i.e. a resistance of $$10$$Ω      is connected in  parallel across Q.  So net resistance  is $$10Q10+Q$$     .Now  the balance point shifts to $$50$$ cm i.e.$$P(10Q10+Q)=1$$     ⇒$$23=1010+Q$$     ⇒$$20+2Q=30$$     ∴$$Q=5$$Ω     and        $$P=103$$Ω

In a meter bridge, the gaps are closed by two resistances P and Q and the balance point is obtained at $40 c m$ . when Q is shunted by a resistance of $10 Ω$ , the balance point shifts to $50 c m$ . the values of P and Q are

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In a meter bridge, the gaps are closed by two resistances P and Q and the balance point is obtained at 40 cm . when Q is shunted by a resistance of 10 Ω , the balance point shifts to 50 cm . the values of P and Q are

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In a meter bridge, the gaps are closed by two resistances P and Q and the balance point is obtained at $40 c m$ . when Q is shunted by a resistance of $10 Ω$ , the balance point shifts to $50 c m$ . the values of P and Q are