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Q.

In the meter bridge shown in figure, distance of the null point N from end A is 40 cm. When a 20Ω resistor is connected in series with P, the null point is displaced to the right by 20 cm. Then value of Q is

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a

24Ω

b

18Ω

c

10Ω

d

12Ω

answer is A.

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Detailed Solution

Initially,  PQ=40100−40⇒PQ=23.  .  . 1Finally,    P+20Q=40+20100−40+20⇒PQ+20Q=32  .  .  .   2Solving,   Q=65×20 Ω=24 Ω
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In the meter bridge shown in figure, distance of the null point N from end A is 40 cm. When a 20Ω resistor is connected in series with P, the null point is displaced to the right by 20 cm. Then value of Q is