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Questions  

In a metre bridge [Fig], the gaps are closed by two resistances P and Q and the balance point is obtained 

at 40 cm. When Q is shunted by resistance of 10 Ω, the balance point shifts to 50 cm. The values of P and Q are

a
(10/3)Ω,5Ω
b
20Ω,30Ω
c
10Ω,15Ω
d
5Ω,(15/2)Ω

detailed solution

Correct option is A

For the balance of metre bridgePQ=RS=4060=23or P=23Q……….(1)When Q is shunted by a resistance of 10 Ω then net resistance in this gap should be a parallel combination of Q and 10 Ω resistance i.e., 10Q /10 +Q).Now the balance shifts to 50 cm i.e., R = 50cm and S = 50 cm. In this caseP[10Q/(10+Q)]=5050=1……..(2)Substituting the value of  P from eq. (1) in eq. (2), we get(2/3)Q[10Q/(10+Q)]=1Solving we get Q=5ΩFrom eq. (1),  P=23×5=103Ω

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In meterbridge experiment when a resistance wire is connected in the left gap, the balance point is found at 30 cm. When the wire is replaced by another wire, the balance point is found at 60 cm. Find the balance point when the two wires connected in series.


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