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 A 1 MeV positron and a 1 MeV electron meet each  other moving in opposite directions. They annihilate each other by emitting two photons. If the rest mass energy of an electron and positron  is 0.51 MeV, then the wavelength of each photon is

a
5.1×10-3A0
b
10.2×10-3A0
c
8.2×10-3A0
d
6.2×10-3A0

detailed solution

Correct option is C

Total energy before annihilation  1+1+2x0.51=3.02 MeV    energy of each photon 1.51 MeVwavelength λ=124001.51×106=8.2×10-3A0

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