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Q.

A 2 MeV proton is moving perpendicular to a uniform magnetic field 2 .5 T. The force on the proton is

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a

2.5x10-10N

b

8x10-11 N

c

2.5 x10-11 N

d

8 x10-12 N

answer is D.

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Detailed Solution

12mv2=2×106eV=2×106×e joules ∴ v=4×106×em1/2F=evB=eB4×106×em1/2=1.6×10−19(2⋅5)4×106×1.6×10−191.67×10−271/2=8×10−12N
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