Questions
A 2 MeV proton is moving perpendicular to a uniform magnetic field 2 .5 T. The force on the proton is
detailed solution
Correct option is D
12mv2=2×106eV=2×106×e joules ∴ v=4×106×em1/2F=evB=eB4×106×em1/2=1.6×10−19(2⋅5)4×106×1.6×10−191.67×10−271/2=8×10−12NTalk to our academic expert!
Similar Questions
A charged beam consisting of electrons and positrons enter into a region of uniform magnetic field B perpendicular to field, with a speed v. The maximum separation between an electron and a positron will be (mass of electron = mass of positron = m)
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