Questions
A 2 MeV proton is moving perpendicular to a uniform magnetic field of 2.5 T. The force on the proton is
detailed solution
Correct option is D
12mv2=2×1.6×10−19×106121.6×10−27v2=2×1.6×10−13v2=4×1014v=2×107F=1.6×10−19×2×107×2.5=8×10−12NTalk to our academic expert!
Similar Questions
A charged beam consisting of electrons and positrons enter into a region of uniform magnetic field B perpendicular to field, with a speed v. The maximum separation between an electron and a positron will be (mass of electron = mass of positron = m)
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