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Q.

A 2 MeV proton is moving perpendicular to a uniform magnetic field of 2.5 T. The force on the proton is

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a

2.5 × 10-10 N

b

8 × 10-11 N

c

2.5 × 10-11 N

d

8 × 10-12 N

answer is D.

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Detailed Solution

12mv2=2×1.6×10−19×106121.6×10−27v2=2×1.6×10−13v2=4×1014v=2×107F=1.6×10−19×2×107×2.5=8×10−12N
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