Questions
A 2 MeV proton is moving perpendicular to a uniform magnetic field of 2.5 T. The force on the proton is
a
2.5 × 10–10 N
b
8 × 10–11 N
c
2.5 × 10–11 N
d
8 × 10–12 N
detailed solution
Correct option is D
12mv2=2×1.6×10−19×106121.6×10−27V2=2×1.6×10−13V2=4×1014V=2×107F=1.6×10−19×2×107×2.5=8×10−12NTalk to our academic expert!
Similar Questions
In the network shown, when switch S is open balancing length AN1 = 60 cm and when the switch S is closed, balancing length AN2 = 50 cm. then the value of r is
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