A 2 MeV proton is moving perpendicular to a uniform magnetic field of 2.5 T. The force on the proton is
2.5 × 10–10 N
8 × 10–11 N
2.5 × 10–11 N
8 × 10–12 N
12mv2=2×1.6×10−19×106121.6×10−27V2=2×1.6×10−13V2=4×1014V=2×107F=1.6×10−19×2×107×2.5=8×10−12N