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Questions  

1 mg gold undergoes decay with 2.7 days half- life period amount left after 8.1 days is

a
0.91 mg
b
0.25 mg
c
0.5 mg
d
0.125 mg

detailed solution

Correct option is D

N=N012n⇒N=N012t/T1/2 ⇒N=1 x 128.12.7=123=18 ⇒N=18mg=0.125 mg

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