First slide

Inductance

Question

A 100 mH coil carries a current of 1 ampere. Energy stored in its magnetic field is

Moderate

A

0.5 J
B

1 J
C

0.05 J
D

0.1 J

Solution

$Energy = \frac{1}{2} {LI}^{2} = \frac{1}{2} \times 100 \times 10^{- 3} \times 1^{2} = 0 .05 J$

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