First slide

Inductance

Question

A 50 mH coil carries a current of 2 ampere. The energy stored in joules is

Moderate

A

1
B

0.1
C

0.05
D

0.5

Solution

$Energy stored E = \frac{1}{2} {Li}^{2} = \frac{1}{2} \times 50 \times 10^{- 3} \times 4 = 0 .1 J$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App