Questions
M.I. of a circular loop of radius R about the axis of rotation parallel to horizontal diameter at a distance R/2 from it is
detailed solution
Correct option is D
Applying theorem of ∥ axes. I=I0+M(R/2)2=12MR2+MR24=34MR2 .Talk to our academic expert!
Similar Questions
The radius of gyration of a rod of length L and mass M about an axis perpendicular to its length and passing through a point at a distance L/3 from one of its ends is
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