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M.I of a solid sphere about its diameter is
detailed solution
Correct option is D
25MR2=64---(1) Vbig=nVsmall 43πR3=n43πr3 r=R2 m∝R3m=Vρ m2m1=R2R13=R12R13=18 m2=M8 For small spheres m=M8,r=R2 I'=25mr2=25×M8×(R2)2 = 132(25MR2)=2kgm2Talk to our academic expert!
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The radius of gyration of a rod of length L and mass M about an axis perpendicular to its length and passing through a point at a distance L/3 from one of its ends is
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