M.I of a solid sphere about its diameter is 64 kgm2 . If that sphere is recast into 8 identical small spheres, then M.I. of such small sphere about its diameter is
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a
8kgm2
b
4kgm2
c
3kgm2
d
2kgm2
answer is D.
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Detailed Solution
25MR2=64---(1) Vbig=nVsmall 43πR3=n43πr3 r=R2 m∝R3m=Vρ m2m1=R2R13=R12R13=18 m2=M8 For small spheres m=M8,r=R2 I'=25mr2=25×M8×(R2)2 = 132(25MR2)=2kgm2