First slide

Diffraction

Question

A microscope has its numerical aperture of 0.16. If wavelength of light used is $5500 \overset{o}{A},$ The resolving power of the microscope is

Moderate

A

$4.6 x 10^{- 5}$
B

$2.9 x 10^{- 5}$
C

$3.2 x 10^{- 5}$
D

$5.8 x 10^{- 5}$

Solution

(4)
$\begin{array}{l} N . A . = μ \sin θ = 0.16 \\ λ = 5500 \overset{o}{A} = 55 \times 10^{- 8} m \\ ∴ Re s o l v i n g p o w e r = \frac{2 μ \sin θ}{λ} = \frac{2 (N . A)}{λ} = \frac{2 \times 0.16}{55 \times 10^{- 8}} m^{- 1} \\ = 5.8 \times 10^{5} m^{- 1} \end{array}$

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