Questions
In Millikan's oil drop experiment an oil drop carrying a charge Q is held stationary by a potential difference 2400 V between the plates. To keep a drop of half the radius stationary the potential difference had to be made 600 V. What is the charge on the second drop
detailed solution
Correct option is B
In balance condition ⇒QE=mg⇒QVd=43πr3ρg⇒Q∝r3V⇒Q1Q2=r1r23×V2V1⇒QQ2=rr/23×6002400=2⇒Q2=Q/2Talk to our academic expert!
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Figure shows three points A, B and C in a region of uniform electric field . The line AB is perpendicular and BC is parallel to the field lines. Then which of the following holds good. Where represent the electric potential at points A, B and C respectively
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