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The minimum energy needed to break carbon of 12.000 amu into three is $α$ particles (mass of $α$ particle = 4.0038 amu)

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10.6 Mev

1.06 Mev

5.36 Mev

0.106 Mev

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detailed solution

Correct option is A

mass defect 3mα -mC=( 3 x4.0038 -12) amu =0.0114 amu energy equivalent 935 x 0.0114 Mev =10.6 MeV

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The minimum energy needed to break carbon of 12.000 amu into three is α particles (mass of α particle = 4.0038 amu)

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The minimum energy needed to break carbon of 12.000 amu into three is $α$ particles (mass of $α$ particle = 4.0038 amu)