The minimum force required to move a body up an inclined plane is three times the minimum force required to prevent it from sliding down the plane. If coefficient of friction between the body and inclined plane is $$123$$, the angle of inclination of the plane with horizontal is

Question

The minimum force required to move a body up an inclined plane is three times the minimum force required to prevent it from sliding down the plane. If coefficient of friction between the body and inclined plane is $$123$$, the angle of inclination of the plane with horizontal is

Infinity Learn · Accepted Answer

Minimum force required to stop sliding is $$mg($$$$sin$$⁡ θ−μ$$cos$$ ⁡θ$$)$$ and minimum force required to push it up is $$mg($$$$sin$$⁡ θ$$+$$μ$$cos$$⁡ θ$$)$$ according to given condition $$mg($$$$sin$$⁡ θ$$+$$μ$$cos$$⁡ θ$$)=3mg($$$$sin$$ ⁡θ−μ$$cos$$ ⁡θ$$)putting$$ μ$$=123$$ after solving θ$$=30$$∘

The minimum force required to move a body up an inclined plane is three times the minimum force required to prevent it from sliding down the plane. If coefficient of friction between the body and inclined plane is $\frac{1}{2 \sqrt{3}}$ , the angle of inclination of the plane with horizontal is

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The minimum force required to move a body up an inclined plane is three times the minimum force required to prevent it from sliding down the plane. If coefficient of friction between the body and inclined plane is 123, the angle of inclination of the plane with horizontal is

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The minimum force required to move a body up an inclined plane is three times the minimum force required to prevent it from sliding down the plane. If coefficient of friction between the body and inclined plane is $\frac{1}{2 \sqrt{3}}$ , the angle of inclination of the plane with horizontal is