The minimum force required to move a body up an inclined plane is three times the minimum force required to prevent it from sliding down the plane. If coefficient of friction between the body and inclined plane is 123, the angle of inclination of the plane with horizontal is

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60°

45°

30°

15°

answer is C.

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Detailed Solution

Minimum force required to stop sliding is mg(sin⁡ θ−μcos ⁡θ) and minimum force required to push it up is mg(sin⁡ θ+μcos⁡ θ) according to given condition mg(sin⁡ θ+μcos⁡ θ)=3mg(sin ⁡θ−μcos ⁡θ)putting μ=123 after solving θ=30∘

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