First slide

Fluid statics

Question

The minimum horizontal acceleration of the container so that the pressure at the point A of the container becomes atmospheric is (The tank is of sufficient height)

Moderate

A

$\frac{3}{2} g$
B

$\frac{4}{3} g$
C

$\frac{4}{2} g$
D

$\frac{3}{4} g$

Solution

Volume equality gives
$2 \times 3 = \frac{1}{2} \times h \times 3 \Rightarrow h = 4 m$
$∴ \tan θ = \frac{4}{3} = \frac{a}{g} \Rightarrow a = \frac{4}{3} g$

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