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The minimum intensity of light to be detected by human eye is $10^{- 10} W / m^{2} .$ The number of photons of wavelength $5.6 \times 10^{7} m$ entering the eye, with pupil area $10^{6} m^{2}$ , per second for vision will be nearly

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detailed solution

Correct option is C

By using I=PA; where P=radiation power⇒P=I×A⇒nhctλ=IA⇒nt=IAλhcHence number of photons entering per sec the eyent=10−10×10−6×56×10−76.6×10−34×3×108=300.

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The minimum intensity of light to be detected by human eye is 10−10W/m2. The number of photons of wavelength 5.6×107 m entering the eye, with pupil area 106m2, per second for vision will be nearly

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The minimum intensity of light to be detected by human eye is $10^{- 10} W / m^{2} .$ The number of photons of wavelength $5.6 \times 10^{7} m$ entering the eye, with pupil area $10^{6} m^{2}$ , per second for vision will be nearly