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The minimum intensity of light to be detected by human eye is $10^{- 10} W m^{- 2}$ .The number of photons of wavelength $5.6 \times 10^{- 7} m$ entering the eye, with pupil area $10^{- 6} m^{2}$ , per second for vision will be nearly

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Correct option is C

energy entering into eye per sec 10-10×10-6=10-16 joules. energy of each photon is hcλno of photons entering per sec n=10-16energy of each photon=10-16×5.6×10-76.6×10-34×3×108=103×5.619.8≈300

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The minimum intensity of light to be detected by human eye is10-10Wm-2.The number of photons of wavelength 5.6×10-7m entering the eye, with pupil area10-6m2, per second for vision will be nearly

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The minimum intensity of light to be detected by human eye is $10^{- 10} W m^{- 2}$ .The number of photons of wavelength $5.6 \times 10^{- 7} m$ entering the eye, with pupil area $10^{- 6} m^{2}$ , per second for vision will be nearly