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The minimum intensity of light to be detected by human eye is10-10Wm-2.The number of photons of wavelength 5.6×10-7m entering the eye, with pupil area10-6m2, per second for vision will be nearly

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a

100

b

200

c

300

d

400

answer is C.

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Detailed Solution

energy entering into eye per sec 10-10×10-6=10-16 joules. energy of each photon is hcλno of photons entering per sec n=10-16energy of each photon=10-16×5.6×10-76.6×10-34×3×108=103×5.619.8≈300

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