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The minimum intensity of light to be detected by human eye is ${10^{ - 10}}W/{m^2}$ . The number of photons of wavelength $5.6 \times {10^{ - 7}}m$ entering the eye, with pupil area 10^-6 m² , per second for vision will be nearly

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detailed solution

Correct option is C

By using where P = radiation power⇒ ⇒ ⇒ Hence number of photons entering per sec the eye =300

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The minimum intensity of light to be detected by human eye is . The number of photons of wavelength entering the eye, with pupil area 10-6 m2 , per second for vision will be nearly

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Ready to Test Your Skills?

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The minimum intensity of light to be detected by human eye is ${10^{ - 10}}W/{m^2}$ . The number of photons of wavelength $5.6 \times {10^{ - 7}}m$ entering the eye, with pupil area 10^-6 m² , per second for vision will be nearly