The minimum kinetic energy required for ionization of a hydrogen atom is E1 in case electron is collided with hydrogen atom. It is E2 if the hydrogen ion is collided and E3 when helium ion is collided. Then,
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a
E1=E2=E3
b
E1>E2>E3
c
E1
d
E1>E3>E2
answer is C.
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Detailed Solution
Assuming that ionization occurs as a result of a completely inelastic collision, we can writemv−0=m+mHuwhere m is the mass of incident particle, mH the mass of hydrogen atom, v0 the initial velocity of incident particle, and u the final common velocity of the particle after collision. Prior to collision, the KE of the incident particle wasE0=mv022The total kinetic energy after collisionE=m+mHu22=m2v022m+mHThe decrease in kinetic energy must be equal to ion ionization energy. Therefore,E1=E0−E=mHm+mHE0 i.e., E1E0=11+mmHi.e., the greater the mass m, the smaller the fraction of initial kinetic energy that be used for ionization.
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The minimum kinetic energy required for ionization of a hydrogen atom is E1 in case electron is collided with hydrogen atom. It is E2 if the hydrogen ion is collided and E3 when helium ion is collided. Then,