Q.

The minimum kinetic energy required for ionization of a hydrogen atom is E1 in case electron is collided with hydrogen atom. It is E2 if the hydrogen ion is collided and E3 when helium ion is collided. Then,

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a

E1=E2=E3

b

E1>E2>E3

c

E1

d

E1>E3>E2

answer is C.

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Detailed Solution

Assuming that ionization occurs as a result of a completely inelastic collision, we can writemv−0=m+mHuwhere m is the mass of incident particle, mH the mass of hydrogen atom, v0 the initial velocity of incident particle, and u the final common velocity of the particle after collision. Prior to collision, the KE of the incident particle wasE0=mv022The total kinetic energy after collisionE=m+mHu22=m2v022m+mHThe decrease in kinetic energy must be equal to ion ionization energy. Therefore,E1=E0−E=mHm+mHE0 i.e.,  E1E0=11+mmHi.e., the greater the mass m, the smaller the fraction of initial kinetic energy that be used for ionization.
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The minimum kinetic energy required for ionization of a hydrogen atom is E1 in case electron is collided with hydrogen atom. It is E2 if the hydrogen ion is collided and E3 when helium ion is collided. Then,