The minimum light intensity that can be perceived by the eye is about 10-10 W /m2 .The number of photons of wavelength5.6 x10-7 m that must enter the pupil of are 10-6m2 per sec for vision is approximately (use h =6.6x10-34 Joule -sec)
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a
3x102 photons
b
3x103 photons
c
3 x104 photons
d
3 x 105 photons
answer is A.
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Detailed Solution
Given that I=10−10W/m2=10−10Js−1m−2 Let the number of photons required be n. Then nhv10−6=10−10 or n=10−6×10−10hv or n=10−16λhc =10−16×5⋅6×10−76⋅62×10−343×108=3×102 photons