First slide

Ray optics

Question

Minimum magnifying power of an astronomical telescope is 20. If the focal length of the eyepiece is 5 cm, then distance between the objective and eyepiece is

Easy

A

100 cm
B

95 cm
C

105 cm
D

110 cm

Solution

$\begin{array}{l} f_{e} = 5 f_{0} = 100 \\ L = f_{0} + f_{e} = 105 \end{array}$

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