The minimum number of cells in mixed grouping required to produce a maximum current of 1.5 A through an external resistance of 30Ω ,given the emf of each cell is 1.5 V and internal resistance is 1Ω is
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a
30
b
120
c
40
d
60
answer is B.
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Detailed Solution
imax=mE2r=nE2Rn = number of cells in each row.m = number of rows.1.5=1.5×n2×30n=601.5=1.5×m2×1m=?∴ total no of cells; = n x m = 2 x 60 = 120