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Q.

In 10 minutes temperature of a body falls from 100°C to 60°C. If cooling of body obeys Newton’slaw, find the temperature of body after next 10 minutes (Temperature of surrounding is 20°C)

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a

20°C

b

40°C

c

50°C

d

30°C

answer is B.

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Detailed Solution

θ2−θ1t=Kθ1+θ22−θa4010=k(80−20)⇒k=11560−θ10=11560+θ2−20⇒60−θ=2360+θ−402⇒180−3θ=20+θ⇒θ=1604=40∘C
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