Mirror is moving towards the particles (negative  x-axis) with speed  2cm/sec. Particles A and B are moving with speeds of 102 cm/sec and 5 cm/sec respectively in the direction shown in figure. Magnitude of velocity of image of the particle B with respect to image of A is

Velocity of image normal to the plane of mirror is  Vi=2Vm−VobjectVelocity of image parallel to the plane of mirror is  Vi=VobjectVelocity of particle image B ,  VBi=2-2i^-−5i^=i^Velocity of particle A is  =102cos45∘i^+102sin45∘j^Velocity of image of particle A perpendicular to the mirror,  VAix=2-2i^-10i^=14−i^Velocity of image of particle A parallel to mirrorVAiy=10j^∴VAi=−14i^+10j^Relative velocity of image  VBAi=VBi−VAi=i^−14−i^+10j^=15i^−10j^∴VBAi=152+102=325cm/secTherefore, the correct answer is  18.03