Q.
Mirror is moving towards the particles (negative x-axis) with speed 2cm/sec. Particles A and B are moving with speeds of 102 cm/sec and 5 cm/sec respectively in the direction shown in figure. Magnitude of velocity of image of the particle B with respect to image of A is
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answer is 0018.03.
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Detailed Solution
Velocity of image normal to the plane of mirror is Vi=2Vm−VobjectVelocity of image parallel to the plane of mirror is Vi=VobjectVelocity of particle image B , VBi=2-2i^-−5i^=i^Velocity of particle A is =102cos45∘i^+102sin45∘j^Velocity of image of particle A perpendicular to the mirror, VAix=2-2i^-10i^=14−i^Velocity of image of particle A parallel to mirrorVAiy=10j^∴VAi=−14i^+10j^Relative velocity of image VBAi=VBi−VAi=i^−14−i^+10j^=15i^−10j^∴VBAi=152+102=325cm/secTherefore, the correct answer is 18.03
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