A mixture of ideal gas containing 5 moles of monatomic gas and 1 mole of rigid diatomic gas is initially at pressure P0, volume V0, and temperature T0. If the gas mixture is adiabatically compressed to a volume V0/4, then the correct statement(s) is/are, (Given 21.2 = 2.3 ; 23.2 = 9.2 ; R is gas constant)

P1=5RToVoP2=RT0VP1+P2=Po=6RT0V0Ymixture =5CP1+(1)CP25CV1+(1)CV2=5×5R2+(1)7R25×3R2+(1)5R2=3220=1.6PVγ= constant ⇒P0V01.6=PV0/41.6⇒P=P0(4)1.6=Po23.2⇒P=9.2P0 Work =W=P2V2−P1V11−γ=9.2P0V04−P0V01−1.6=(2.3−1)PoV0−0.6=1.3×6RT0−0.6⇒W=−13RT0⇒|W|=13RT0TVγ−1= constant ⇒TiViγ−1=TfVfγ−1⇒T0V00.6=TfV040.6⇒Tf=(2)1.2T0=2.3T0 Kinetic Energy =nCVmixTf=(6)R1.6−12.3T0=23RT0