First slide

Simple hormonic motion

Question

Mkg weight is suspended from a weightless spring and it has time period T. If now 4 M kg weight is suspended from the same spring, the new time period will be:

Easy

A

T
B

2T
C

T/2
D

4T

Solution

$T \propto \sqrt{M} \Rightarrow \frac{T'}{T} = \sqrt{\frac{4 M}{m}} \Rightarrow T' = 2 T$

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