A modern grand – prix racing car of mass m is travelling on a flat track in a circular arc of radius R with a speed v. If the coefficient of static friction between the tyres and the track is μs, then the magnitude of negative lift FL acting downwards on the car is: (Assume forces on the four tyres are identical and g=acceleration due to gravity)

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mv2μSR+g

mv2μSR−g

−mg+v2μSR

mg−v2μSR

answer is B.

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Detailed Solution

Friction provides centripetal force.mv2R=μsN If we consider FL is negative lift then N=mg+FL⇒μsmg+FL=mv2R ⇒FL=mv2μsR−mg

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