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Q.

A modern grand – prix racing car of mass m is travelling on a flat track in a circular arc of radius R with a speed  v. If the coefficient of static friction between the tyres and the track is  μs, then the magnitude of negative lift  FL acting downwards on the car is: (Assume forces on the four tyres are identical and g=acceleration due to gravity)

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a

mv2μSR+g

b

mv2μSR−g

c

−mg+v2μSR

d

mg−v2μSR

answer is B.

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Detailed Solution

Friction provides centripetal force.mv2R=μsN  If we consider FL is negative lift then N=mg+FL⇒μsmg+FL=mv2R ⇒FL=mv2μsR−mg
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