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Q.

A modern 200 W sodium street lamp emits yellow light of wavelength 0.6 μm. Assuming it to be 25% efficient in converting electrical energy to light, the number ofphotons of yellow light it emits per second is

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a

62×1020

b

3×1019

c

1.5×1020

d

6×1018

answer is C.

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Detailed Solution

Effective power =25100×200W=50W Now, 50=nhv=nhcλn=50λhc=50×0.6×10−66.6×10−34×3×108=1.5×1020
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