A modern 200 watt sodium street lamp emits yellow light of wavelength 0.6μm. Assuming it to be 25% efficient in converting electrical energy to light, the number of photons of yellow light it emits per second is

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6 x 1020

3 x 1019

1.5 x 1020

6 x 1018

answer is C.

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Detailed Solution

effective power = 25100 x200= 50 W 50= nhcλ n=50 x 6.6 x10-34 x3 x1086 x10-7= 1.5x1020

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