4 mole of a diatomic ideal gas are heated at constant pressure from 27°C to 327°C. Internal energy of the gas increases by: (take R = 2 cal/mol-K)

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3000 calorie

6000 calorie

8400 calorie

10000 calorie

answer is B.

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Detailed Solution

∆U=nCV∆T=452R(327-27) =3000R=6000 cal

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