First slide

Specific heat and degrees of freedom

Question

A molecule of a gas has six degrees of freedom. Then the molar specific heat of the gas at constant volume is

Easy

A

$\frac{R}{2}$
B

$R$
C

$\frac{3 R}{2}$
D

$3 R$

Solution

Here, number of degrees of freedom, f = 6
Molar specific heat of the gas at constant volume is $C_{V} = \frac{f}{2} R = \frac{6}{2} R = 3 R$

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