Q.

The molecules of a given mass of gas have rms speed 200 m s-1 at 27 °C and 105 N m-2 pressure. When the absolute temperature is doubled and the pressure is halved, then rms speed (in m s-1) of the molecules of the same gas is _______.

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answer is 282.8.

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Detailed Solution

vrms=3RTm⇒vrms2vrms1=T2T1=2×300300∴ vrms2=vrms12=2002 ms−1=282.8 ms−1
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The molecules of a given mass of gas have rms speed 200 m s-1 at 27 °C and 105 N m-2 pressure. When the absolute temperature is doubled and the pressure is halved, then rms speed (in m s-1) of the molecules of the same gas is _______.