The molecules of a given mass of a gas have rms velocity of 200 ms-1 at 27°C and 10 × 105 Nm-2 pressure. When the temperature and pressure of the gas are respectively, 127°C and 0.05 × 105 Nm-2, the rms velocity of its molecules (in ms-1) is
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a
4003
b
10023
c
1003
d
1002
answer is A.
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Detailed Solution
It is given that, vrms1=200 ms-1,T1=300 K,p1=105Nm-2 T2=400 K,p2=0.05×105Nm-2,vrms2=?As, rms velocity of gas molecules, vrms ∝ T ∵vrms=3RTMFor two different cases,⇒ vrms1vrms2=T1T2⇒200vrms2=300400=34⇒ vrms 2=23×200=4003 ms-1