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Q.

The molecules of a given mass of a gas have rms velocity of 200 ms-1 at 27°C and 10 × 105 Nm-2 pressure. When the temperature and pressure of the gas are respectively, 127°C and 0.05 × 105 Nm-2, the rms velocity of its molecules (in ms-1) is

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a

4003

b

10023

c

1003

d

1002

answer is A.

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Detailed Solution

It is given that,     vrms1=200 ms-1,T1=300 K,p1=105Nm-2           T2=400 K,p2=0.05×105Nm-2,vrms2=?As, rms velocity of gas molecules,                         vrms ∝ T                            ∵vrms=3RTMFor two different cases,⇒             vrms1vrms2=T1T2⇒200vrms2=300400=34⇒             vrms 2=23×200=4003 ms-1
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