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Questions  

The molecules of a given mass of a gas have r.m.s. velocity of 200 ms-1 at 270C and 1.0×105 Nm-2 pressure. When the temperature and pressure of the gas are respectively, 1270C and 0.05×105 Nm-2, the r.m.s. velocity of its molecules in ms-1 is:

a
1002
b
4003
c
10023
d
1003

detailed solution

Correct option is B

v ∝T     ⇒ v200 = 400300   ⇒ v = 200×23  ⇒ v = 200×23m/s⇒  v = 4003m/s

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