The moment of the force, F→=4i^+5j^-6k^ at (2,0,-3), about the point (2,-2,-2) , is given by
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a
-8i^-4j^-7k^
b
-4i^-j^-8k^
c
-7i^-8j^-4k^
d
-7i^-4j^-8k^
answer is D.
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Detailed Solution
Moment of the force is, τ→=r→-r→0×F→ Here, r→0=2i^-2j^-2k^ and r→=2i^+0j^-3k^∴ r→-r→0=(2i^+0j^-3k^)-(2i^-2j^-2k^)=0i^+2j^-k^∴ τ→=i^j^k^02-145-6=-7i^-4j^-8k^